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Problems of the Week – May 13 to May 17

Click here [1] for the Problem Extension Worksheet version of the Problems of the Week.
Click here [2] for an MS Word version of the Problems of the Week.
Click here [3] for the Canadian Problem Extension Worksheet version of the Problems of the Week.
Click here [4] for a Canadian MS Word version of the Problems of the Week.

Lower Elementary:
Question: Grace, Ruby, and James volunteer to walk shelter dogs. Grace walks half as many dogs as Ruby, who walks 5 more dogs than James. James walks 9 dogs. How many dogs did Grace walk?
Answer: 7 dogs
Solution: If Ruby walked 5 more dogs than James, then she walked 9 + 5 = 14 dogs. Grace walked half as many as that, so she walked half of 14 = 7 dogs.

Upper Elementary:
Question: Spot the dog likes to bury bones in the backyard. On Friday, he buried half of his bones. On Saturday, he dug up 3/4 of the bones he buried the day before. If spot started with 72 bones on Friday, then how many bones did he dig up on Saturday?
Answer: 27 bones
Solution: Spot buried half of 72 = 36 bones on Friday. To find out how many bones he dug up on Saturday, first we need to find 1 quarter of 36 by finding half of a half of 36. That’s half of 18, which is 9. Since Spot dug up 3 quarters of the bones he buried, we know that he dug up 9 × 3 = 27 bones on Saturday.

Middle School:
Question: Daniel and his sister Chloe are training their neighbors’ dog. Daniel teaches the dog to sit and speak. Chloe teaches the dog to lie down, roll over, and fetch. They are paid for each trick they teach the dog and get a total of $80. How should they split the money?
Answer: Daniel gets $32. Chloe gets $48.
Solution: Daniel and Chloe together taught the dog 5 tricks, so we need to divide their earnings by 5 first. $80 ÷ 5 = $16 per trick. That means that Daniel gets $16 × 2 = $32 because he taught the dog 2 tricks, and Chloe gets the rest, $48, because she taught the dog the other 3 tricks.

Algebra & Up:
Question: A dog run is three times as long as it is wide. If its perimeter is 104 feet, what is the area of the dog run?
Answer: 507 square feet
Solution: We can represent the relationship between the width and length of the dog run with the equation 3W = L. We can also know that 2 times the width plus 2 times the length of a rectangle is its perimeter, so 2W + 2L = 104. We solve for the length and the width by substituting 3W for L in the second equation, which makes 2W + 6W = 8W = 104. From there, we can find that the width is 13 feet, so the length must be 39 feet. The area is therefore 13 × 39 = 507 feet.