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Problems of the Week – March 12 to 16

Click here [1] for the Problem Extension Worksheet version of the Problems of the Week.
Click here [2] for an MS Word version of the Problems of the Week.
Click here [3] for the Canadian Problem Extension Worksheet version of the Problems of the Week.
Click here [4] for a Canadian MS Word version of the Problems of the Week.

[5]Lower Elementary:
Question: Zachary sold books at a yard sale for 15¢ each and toys for $1.00 each. If he sells 6 books and 3 toys, how much money does Zachary make altogether?
Answer: Zachary makes $3.90.
Solution: Zachary earned 15¢, 6 times for the books. That’s 15, 30, 45, 60, 75, 90¢ for all 6 of the books. He earned $1.00, 3 times for the toys. That’s $3.00 for all 3 of the toys. So, altogether, Zachary earned $0.90 + $3.00 = $3.90.

[6]Upper Elementary:
Question: Eight students are performing songs for their music class recital. Each song is 5 minutes long. If each music student performs 1 song and all 8 students must be done performing by 9:15 PM, then what is the latest time they can start the recital?
Answer: The latest they can start is 8:35 PM.
Solution: The amount of time it takes for all of the students to finish their songs is 8 × 5 = 40 minutes. Since they have to finish the recital by 9:15 PM, we count back 40 minutes before 9:15 PM to 8:35 PM.

[7]Middle School:
Question: A 9-foot tree casts a 6-foot shadow. A songbird casts a 2-inch shadow. A squirrel is twice as tall as the songbird. How tall is the squirrel?
Answer: The squirrel is 6 inches tall.
Solution: The length of the tree’s shadow is two-thirds the height of the tree. So, the length of the songbird’s shadow is two-thirds its height; 2 inches is two-thirds of 3 inches, so the songbird must be 3 inches tall. That means that the squirrel is 6 inches tall because 6 inches is twice as tall as 3 inches.

[8]Algebra and Up:
Question: The profit earned by a cat-sitting company, measured in thousands of dollars, is modeled by the function f(t) = t2 – 8t + 16, wherein t is measured in months and t = 1 is January. During which month does the cat-sitting company earn the least amount of money? How much do they earn?
Answer: They earned $0.00 in April.
Solution: This function is a parabola that opens upward, so the lowest value is at the vertex. To find the month, we find –b/2a = –(–8)/(2 × 1) = 8/2 = 4. So the vertex is at t = 4, which represents the month of April. To find how much they earned, we set t = 4 and solve: 42 – 8(4) + 16 = 16 – 32 + 16 = 0. So, the cat-sitting business earned $0.00 in April.